Hallo, I know, that the normal way to do that is to write the return value of the method to the foreign model, always when a model that affects the return value changes, and than order by that value of the model.
But I have a model whoose objects gets a specific state after they are older than a specific number of days. And i don`t want to use a cronjob or something like that to update the foreign model`s value. So, can someone tell me, how I can order a query set by one of the function of it`s models, in a pinch by reordering the obecjts in a new object array or some kind like that. There are not a lot of records I have to order, so I think there is no performance problem for my kind of application. Thank you! -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
