just for the records ...
it seems to work when filename is not defined with
response["Content-Disposition"] = "attachment; filename=äöü &%%%.pdf"
instead just use
response["Content-Disposition"] = "attachment"
and add the filename to the URL, e.g.
/user/downloads/15/äöü &%%%%.pdf
where
15 is the object-id and the filename has to be urlencoded.
within a template, it looks like this:
{% url attachment_download object.id %}{{ object.attachment.name|
urlencode }}
the view just checks if the attachment with id 15 has been uploaded by
the logged-in user and returns the attachment:
def attachment_download(request, object_id):
import mimetypes
obj = get_object_or_404(UserAttachment, user=request.user,
pk=object_id)
mimetype, encoding = mimetypes.guess_type(fullpath)
mimetype = mimetype or 'application/octet-stream'
response = HttpResponse(obj.attachment.read(), mimetype=mimetype)
response['Content-Length'] = obj.attachment.size
response["Content-Disposition"] = "attachment"
if encoding:
response["Content-Encoding"] = encoding
return response
tested with firefox, safari, chrome, IE7, IE8, opera ... guess it
works.
regards,
patrick
On 21 Nov., 16:31, patrickk <sehmasch...@gmail.com> wrote:
> I need to serve media-files uploaded by users, but only the user who
> uploaded a file should be able to download that file again. therefore,
> I need to check whether the currently logged-in user is the creator of
> that file (ok, that´s easy with using a view).
>
> – of course, serving the media-file via django is not an option.
> – downloading the file (changing the response-header) is not an option
> either since we need to use utf-8 filenames (same goes for xsendfile).
>
> any ideas on how to achieve this? btw, we´re using mod_wsgi.
>
> thanks,
> patrick
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