Oh you want just one record per page? Thats easy. urls.py (r'^page/(?P<page_number>\d+)/$', 'data.views.pagelisting'),
views.py def pagelisting(request, page_number): data_list = Data.objects.filter(pk=page_number) return render_to_response('list.html', {"data_list": data_list}) template list.html {% if datalist %} <ul> {% for data in datalist %} <p>{{ data.text }}</p> {% endfor %} </ul> <a href='http://testsite.com/page/{%pk + 1%}>Next Page<a/> <a href='http://testsite.com/page/{%pk - 1%}>Next Page<a/> {% else %} <p>No data is available.</p> {% endif %} On Oct 15, 6:43 am, David <cthl...@gmail.com> wrote: > Hi Devin > > Thank you for your reply. > > I'm not sure if I've explained myself properly, or if I'm > misinterpreting your reply. What I am aiming for is a form containing > a single record. At the bottom of this form will be the pagination > tools << Prev 1 2 3 etc. which will enable the user to navigate > through the records individually in my form. I was hoping that the > pagination had the ability to know the current records primary key so > that I could render the form with a simple Data.objects.get(pk=1) this > would then achieve the desired effect (I think). -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.