> My Url look like this
>
> di/sub?word=check&type=00&submit=Submit
> -------
> but it shows the error for symbols "?"
> -----------------------------------------------
> i want to print only the word check in this url and it can be anyword
> given by user
Hi Sami,
while you technically *can* make this working, it's not the usual
way of handling URL's. Anything beyond a question mark is a parameter
and is better handled inside your view.
So, your urls.py would look like this:
(r"^wap/di/sub", hellow)
And your view would contain the following code:
def hellow(request):
word = request.GET['word']
return HttpResponse(word)
But you should need two things:
- the code does not contain any error checking (i.e. what happens if
"word" is not provided in the URL
- There is a security issue. Displaying anything that user provides
on the output page *without checking it first* is insecure and can
lead to various security-related issues
I'll leave the JavaScript bit to your excercise as I don't really
understand what you're trying to achieve with that.
Cheers
Jirka
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