Hi Friends! I'm working with django and i have this error: Request Method: GET Request URL: http://127.0.0.1:8000/myapp/New_page/ Django Version: 1.2.3 Exception Type: ValueError Exception Value:
invalid literal for int() with base 10: 'New_page' Exception Location: /usr/local/lib/python2.6/dist-packages/django/db/ models/fields/__init__.py in get_prep_value, line 479 Python Executable: /usr/bin/python Python Version: 2.6.4 Resume, i want that the identify of my webs will be the title of the page. Now, i'm using the "id" of the page, but i want to put the page.title instead page.id The structure of url is : url(r'^(?P<page_title>[^/]+)/$', 'view_page'), is correct? and function view_page is: def view_page(request, page_title): if request.user.is_authenticated(): page_qs = Page.objects.filter(Q(id=page_title) & (Q(author=request.user)|Q(public=True))) else: page_qs = Page.objects.filter(id=page_title, public=True) if page_qs.count() == 0: raise HttpResponseNotAllowed() pag = page_qs[0] return render_to_response( "v/schema.html", {"pag":pag}, context_instance=RequestContext(request)) Someone who wants help me?!! -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.