Thanks for the answers guy, I knew a little bit model forms, but I'll
check out also the other solution.


On 22 Set, 09:29, Matthias Kestenholz <matthias.kestenh...@gmail.com>
wrote:
> On Mon, Sep 20, 2010 at 3:13 PM, Federico Capoano
>
> <nemesis.des...@libero.it> wrote:
> > Hi all,
>
> > I try to explain it clearly.
>
> > I have to develop an application that will implement similar
> > functionality and look of the django admin, but in the frontend.
>
> > So this application will have files management, clients management,
> > and much more similar stuff, with add new, edit, delete, file upload
> > and so on.
>
> > Is there a way you would advice to do this?
>
> There are a few implementations around which try to do something like
> that. One of them is my django_modelviews project -- it's unreleased,
> undocumented, but I use it on several sites in production. Short usage
> instructions:
>
> http://github.com/matthiask/modelviews/
>
> 1. Add django_modelviews to INSTALLED_APPS
> 2. Create a ModelView instance somewhere in your views.py, f.e. for
> your Client model:
>
> from yourapp.models import Client
> from django_modelviews import generic
> client_views = generic.ModelView(Client)
>
> 3. Create a URL entry:
>
> from yourapp.views import client_views
> urlpatterns = patterns('',
>     url(r'^clients/', include(client_views.urls)),
> )
>
> If the code does not work for you or does not fit your needs, maybe it
> can still serve as an inspiration for your own project.
>
> Matthias
>
> --
> Django CMS building toolkit:http://www.feinheit.ch/labs/feincms-django-cms/

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