Not that I'm aware of, in which case I'd say a tag (or even a filter) *is* the "built-in way". No great hardship:
@register.filter def class_name(value): return value.__class__.__name__ On Aug 4, 11:13 am, "David.D" <dengyuanzh...@gmail.com> wrote: > There's no django's built-in way? > > On Aug 4, 10:37 pm, Scott Gould <zinck...@gmail.com> wrote: > > > > > How about writing a simple template tag that takes an object and > > returns object.__class__.__name__? > > > On Aug 4, 10:20 am, "David.D" <dengyuanzh...@gmail.com> wrote: > > > > I did it by adding this to my models: > > > def get_model_name(self): > > > return self.__class__.__name__ > > > > And it works.... > > > > But I don't want to define the 'get_model_name' method in my model. > > > > Is there a built-in way? > > > > Thanks. -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.