On 7/21/06, Malcolm Tredinnick <[EMAIL PROTECTED]> wrote:
>
> On Fri, 2006-07-21 at 15:53 +0800, limodou wrote:
> > On 7/21/06, limodou <[EMAIL PROTECTED]> wrote:
> > > Recently I wrote some ajax code in my django project. And as I
> > > invoking xmlhttprequest to call view methods, and sometimes I see
> > > nothing happened in browser, but I found some messages in development
> > > server's log output, just like:
> > >
> > > [21/Jul/2006 08:35:36] "POST /easyadmin/add/users/TPermission/
> > > HTTP/1.1" 500 46557
> > >
> > > I saw there is a 500 error, but I cann't see the debug page, so I want
> > > to know how to get the errors at this case? Is there an easy way to
> > > output the debug to somewhere manually?
> > >
> >
> > Answer myself:
> >
> > in view method:
> >
> > try:
> >     old code
> > except:
> >     import traceback
> >     traceback.print_exc()
>
> You could also put something in django/views/debug.py I guess.

But hacking code isnot a good way I think.
>
> One of my many Django trees contains the beginnings of integrating
> Python's logger framework into various places in the code in a
> non-intrusive fashion. It's queued behind a few more urgent things at
> the moment, but if nobody else gets to it first I'll get this finished
> one day and that should help in situations like this.
>
> Malcolm
>
good. May be a good thing.

-- 
I like python!
My Blog: http://www.donews.net/limodou
My Django Site: http://www.djangocn.org
NewEdit Maillist: http://groups.google.com/group/NewEdit

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