That was perfect. Thank you. I don't look at the admin docs enough I guess. The following worked:
customers = forms.ModelChoiceField(queryset=Customers.objects.all(), widget=forms.TextInput) On Jun 14, 3:03 pm, Lee Hinde <leehi...@gmail.com> wrote: > On Mon, Jun 14, 2010 at 1:59 PM, geraldcor <gregco...@gmail.com> wrote: > > Hello all, > > > I have a model A that has >4000 records in it. I have just created a > > new model B that has a foreign key to A. I want to be able to create > > an instance of B and save it which is no problem going the normal > > routes. However, I like to use Ajax to make the load times faster > > because a lot of our clients are on slow connections in China. With > > the foreign key <option> field being populated by 4000+ values, the > > load time for the page is quite slow. I would like to leave > > ModelChoiceField off my form and then populate it in my view (or a > > hidden input in my form). However, whenever I just try to save the pk > > number value into the foreign key, I get the error "Cannot assign > > "u'1783'": "MainNode.customers" must be a "Customers" instance." > > > How can I just save a number to the foreign key field? Thanks for any > > advice and help. > > > Greg > > If you're talking about this problem in Admin, look at: > > http://docs.djangoproject.com/en/1.2/ref/contrib/admin/#django.contri... > > If it's your own form, you could do something similar. > > > > -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
