Not sure if this will work as I don't usually do much with model
inheritance but according to docs at:
http://docs.djangoproject.com/en/dev/topics/db/models/#id7
this might work (not pretty, but somewhat minimal code)...
p = Parent1.objects.get(id=1)
try:
p.childa.basemthod()
except:
try:
p.childb.basemethod()
except:
raise Execption("not ChildA or ChildB")
Django adds in the lower cased name of the class as a property when
you query the super class and throws an exception if you access a
property that isn't there. So something like the above "might" work.
And obviously if you have like 5 child classes, this gets ugly very
quickly.
Dan Harris
dih0...@gmail.com
On Jun 8, 3:27 pm, John M <retireonc...@gmail.com> wrote:
> Hmm, that doesn't really get me what I want, it just caches the
> related child objects in one SQL query.
>
> What I want is a single interface and have django figure out what type
> of child object I have (like multiple inheritance but 'better').
>
> So in my example:
>
> p = Parent1.objects.get(id=1)
> p.child.basemethod()
>
> django would know what p.child is (either ChildA or ChildB) and I
> wouldn't need to know.
>
> Is that available?
>
> J
>
> On Jun 8, 11:09 am, Dejan Noveski <dr.m...@gmail.com> wrote:
>
>
>
> >http://docs.djangoproject.com/en/dev/ref/models/querysets/#id4
>
> > select_related()
>
> > On Tue, Jun 8, 2010 at 8:05 PM, John M <retireonc...@gmail.com> wrote:
> > > I've gotten model inheritance working just fine, but was hoping
> > > someone could confirm the best way to access the model.
>
> > > When I have a Base model which has a ForeignKey to a parent table, and
> > > that base model has inherited models after it, how can I refer to only
> > > one name when referencing the parent model.
>
> > > As an example:
>
> > > class Base(models.Model):
> > > parent = models.ForeignKey(Model1)
>
> > > class Meta:
> > > abstract = True
>
> > > def basemethod():
> > > print "hello"
>
> > > class ChildA(Base):
> > > pass
>
> > > class ChildB(Base):
> > > pass
>
> > > p1 = Model1()
> > > p1.save
> > > x = ChildA()
> > > x.parent = P1
> > > x.save()
>
> > > p2 = Model1()
> > > p2.save()
> > > y = ChildB()
> > > y.parent = P1
> > > y.save()
>
> > > Now, I want to access the children from the parent, but I don't want
> > > to have to know what base class they are, is there a way to do that?
> > > Right now I'm using a property which figures it out based on some
> > > other fields, but would love to be able to say
>
> > > p = Parent1.objects.get(id=1)
> > > p.child.basemethod()
>
> > > Is this possible?
>
> > > Thanks
>
> > > --
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> > > "Django users" group.
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>
> > --
> > --
> > Dejan Noveski
> > Web Developer
> > dr.m...@gmail.com
> > Twitter:http://twitter.com/dekomote|LinkedIn:http://mk.linkedin.com/in/dejannoveski
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