That's exactly what I'm looking to do, but as I have never done it
before I am having trouble gaining the base of knowledge needed to
accomplish the task.
Your series of questions actually helps in that it offers a quick map
of the process for doing what it is I'd like to do.
Here is my first thought for how to do this:
feed = urllib.urlopen('http://example.xml/data.xml')
tree = ElementTree.parse(feed)
for obj in serializers.deserialize(feed, data):
obj.save()
On Jun 4, 11:14 am, Venkatraman S <venka...@gmail.com> wrote:
> On Fri, Jun 4, 2010 at 9:40 PM, Nick <nickt...@gmail.com> wrote:
> > I have been playing with
> > ElementTree and BeautifulSoup but there is just something I'm not
> > getting.
>
> What is the problem that you are facing? if your XML is well defined, then
> parse it, extract the data, convert that into objects and good to go ?
> Right?
> Or am i missing something?
>
> -V-http://twitter.com/venkasub
--
You received this message because you are subscribed to the Google Groups
"Django users" group.
To post to this group, send email to django-us...@googlegroups.com.
To unsubscribe from this group, send email to
django-users+unsubscr...@googlegroups.com.
For more options, visit this group at
http://groups.google.com/group/django-users?hl=en.
