Create a ModelForm for your model (A), set the queryset to what you want on the appropriate field (n), and then register that ModelForm for admin use in your admins.py.
Regards Scott On Jun 4, 6:14 am, Massimiliano della Rovere <massimiliano.dellarov...@gmail.com> wrote: > When displayed in the Admin interfaces, I'd like to filter the values > of n, so that instances of N already linked to other instances of A > sharing the same instance of o are not shown: > so when you edit an instance of A (let's call it "a"), you see only > the instances of n in use by a and the unsed ones (in the context of > o). > > The problem is that I am not allowd to write self.choices_for_n() > > Does anybody know any solution for this? > > class A(models.Model): > o = models.ForeignKey(O) > p = models.ManyToManyField(P) > n = models.ManyToManyField(N, limit_choices_to=self.choices_for_n()) > > def choices_for_n(self): > unwanted = [] > for z in self.o.z_set.all(): > if z.id == self.id: > continue > unwanted += [z.id for z in z.n] > for n in N.objects.exclude(id__in=unwanted): > yield n.id -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
