On Jun 26, 2006, at 12:43 PM, Glenn Tenney wrote: > > [...] > 2) Also within your application, write a global function that (a) > immediately checks to see if it's the first time it's invoked each day > (or whatever interval), and then, if it is the first time, (b) does > all of the repetitive tasks... This translates to: the first click > within the desired interval automatically performs the pending > repetitive tasks. Note: this is not always a good solution (but can > sometimes be fine), since you might have tasks that need to be done > every interval even if no one clicks your site, or the tasks run a > long time, etc. This can be combined with #1 above in that the URL in > #1 above would only need to be some regular URL into your application > since ANY click to your application will do the repetitive task once > each interval. [...]
I've found a better solution with signals and the dispatcher. The essence is that you raise a signal every time someone views the relevant page, for instance, a "Recent Flickr Photos" page. In the relevant models.py file, you'll have attached a function call to be called on the raising of that signal. That function should check when the last time it was run, if it was run more than X minutes ago, have it call the relevant Flickr synchronization code, or whatever else you want it to do. I'm using that method on a current site and it works very well. On top of that, it doesn't rely on OS-specific tools to work. Maybe that would be a nice contrib app: a "fake" cron using the above method. Just a thought, anyways. -Tyson --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users -~----------~----~----~----~------~----~------~--~---
