Hello everyone,
A (long) question:
I have two models, linked by a single key. LinkClass ("search engines",
...) and Link ("http://www.google.com";, "http://www.yahoo.com";)
Now, in Python I can do:
for link_class in LinkClass.objects.all():
print link_class.name
for link in link_class.link_set.all().order_by("name"):
print "\t", link
In the templates I do:
{% for link_class in object_list %}
<h2>{{ link_class.name }}</h2>
<ul>
{% for link in link_class.objects.all %}
<li>{{ link.name }}
{% endfor %}
</ul>
{% endfor %}
But I can't "order by" in the link_class.objects.all (or I missed some
functionality)!
Now there's a few solutions I see, none of which I like:
1. use the dictsort or something equal in the templating language: I
don't like this as it doesn't use the underlying DB for the sorting,
thus is slow (afaic...).
2. add a function:
def ordered_links(self):
return self.link_set.all().order_by("name")
to the link class. I don't like this, because if I add another link type
( say class VerySpecialLinks ) which has the LinkClass as foreign key,
this function will not work for this special type of link and I'll have
to write another function in LinkClass.
3. write a view and fill a dict with the info I want, pass the dict then
print via the template. This seems ridiculous as would be writing the
same twice (once in python, once in the templating).
Is there a nice AND simple solution for this?
- bram
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