Hey all,
I've configured django with Apache and mod_python, and I have
Apache serving static media. If all media is to have a MEDIA_URL
prefix, how do I grab this value out of the project settings?
Currently, my solution is to write a filter, like so:
in myproject/myapp/templatetags/mediaurl.py:
from django.core.template import Library
register = Library()
def media_url():
try:
from django.conf.settings import MEDIA_URL
except ImportError:
return ''
return MEDIA_URL
media_url = register.simple_tag(media_url)
I blatantly stole this code from adminmedia.py from the admin app
in myproject/templates/base.html:
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd";>
<html xmlns="http://www.w3.org/1999/xhtml"; xml:lang="en" lang="en">
<head>
<link rel="stylesheet" type="text/css" href="{% block stylesheet
%}{% load mediaurl %}{% media_url %}css/base.css{% end\
block %}" />
<title>{% block title %}Website Title{% endblock %}</title>
</head>
As you can see, I load the mediaurl filter, and then inject the
media_url value. My question is, is this the right way to do this? I
can't imagine that I'm the only one who has a need to read project
settings. Is there a built-in way of grabbing project settings? Maybe
a filter like the one I wrote? I wish there was more API
documentation...
Thanks!
Mateja
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