Hi,

On Wed, 2006-02-22 at 19:12 -0800, Luke Skibinski Holt wrote:
> dt = datetime.now()
> dt.replace(day=28, month=2)
> wd = dt.weekday()
> sat = dt.replace(day=dt.day+(5-wd))
> sun = dt.replace(day=dt.day+(6-wd))

>>> from datetime import datetime, timedelta
>>> dt = datetime(2006, 2, 28)
>>> wd = dt.weekday()
>>> wd
1
>>> sat = dt + timedelta(5-wd)
>>> sat
datetime.datetime(2006, 3, 4, 0, 0)

HTH,

Russell
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