#28047: Regression in query set against 1.10
-------------------------------------+-------------------------------------
Reporter: Thierry Bastian | Owner: nobody
Type: Bug | Status: new
Component: Database layer | Version: 1.11
(models, ORM) |
Severity: Normal | Resolution:
Keywords: regression | Triage Stage:
| Unreviewed
Has patch: 0 | Needs documentation: 0
Needs tests: 0 | Patch needs improvement: 0
Easy pickings: 0 | UI/UX: 0
-------------------------------------+-------------------------------------
Description changed by Ingo Klöcker:
Old description:
> I have this (simplified)
>
> from django.db import models
> class Foo(models.Model):
> class Meta:
> app_label = 'inventory'
> pass
>
> class Bar(models.Model):
> class Meta:
> app_label = 'inventory'
> foo = models.OneToOneField(Foo, primary_key=True,
> on_delete=models.CASCADE)
>
> Of course you need an app named inventory. But just use this and try to
> create a query set like this:
>
> Bar.objects.filter(foo__in=Foo.objects.all())
>
> Obviously I had different criteria.
>
> Creating that query set says:
> "django.core.exceptions.FieldError: Cannot resolve keyword 'foo' into
> field. Choices are: bar, id"
>
> That was working just fine in Django 1.10
New description:
I have this (simplified)
{{{#!python
from django.db import models
class Foo(models.Model):
class Meta:
app_label = 'inventory'
pass
class Bar(models.Model):
class Meta:
app_label = 'inventory'
foo = models.OneToOneField(Foo, primary_key=True,
on_delete=models.CASCADE)
}}}
Of course you need an app named inventory. But just use this and try to
create a query set like this:
{{{#!python
Bar.objects.filter(foo__in=Foo.objects.all())
}}}
Obviously I had different criteria.
Creating that query set says:
"django.core.exceptions.FieldError: Cannot resolve keyword 'foo' into
field. Choices are: bar, id"
That was working just fine in Django 1.10
--
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Ticket URL: <https://code.djangoproject.com/ticket/28047#comment:1>
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