#27277: Error in generation of SQL query when have a ForeignKey with Model with
ChoiceField
-------------------------------------+-------------------------------------
Reporter: Cátia Simões | Owner: nobody
Type: Bug | Status: new
Component: Database layer | Version: 1.9
(models, ORM) |
Severity: Normal | Resolution:
Keywords: SQL, QUERYSET, | Triage Stage:
CHOICEFIELD | Unreviewed
Has patch: 0 | Needs documentation: 0
Needs tests: 0 | Patch needs improvement: 0
Easy pickings: 0 | UI/UX: 0
-------------------------------------+-------------------------------------
Changes (by Tim Graham):
* needs_docs: => 0
* severity: Release blocker => Normal
* needs_tests: => 0
* needs_better_patch: => 0
Comment:
Can you please edit your models to form a minimal example to reproduce?
For example, currently you have undefined references to `Languages` and
`GENDER` which make trying to reproduce this more difficult. I'm surprised
if Django is generating `case / when` SQL for the queryset you gave. Are
you sure about this? Are you using `django.db.backends.mysql` in the
`DATABASES` setting?
--
Ticket URL: <https://code.djangoproject.com/ticket/27277#comment:1>
Django <https://code.djangoproject.com/>
The Web framework for perfectionists with deadlines.
--
You received this message because you are subscribed to the Google Groups
"Django updates" group.
To unsubscribe from this group and stop receiving emails from it, send an email
to [email protected].
To post to this group, send email to [email protected].
To view this discussion on the web visit
https://groups.google.com/d/msgid/django-updates/065.670ace6998997941d9bb72b12de169df%40djangoproject.com.
For more options, visit https://groups.google.com/d/optout.