#25198: Django's model_to_dict should return ALL fields, including hidden
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Reporter: 1st | Owner: nobody
Type: Uncategorized | Status: new
Component: Core | Version: master
(Serialization) |
Severity: Normal | Resolution:
Keywords: model serialization | Triage Stage:
| Unreviewed
Has patch: 0 | Needs documentation: 0
Needs tests: 0 | Patch needs improvement: 0
Easy pickings: 0 | UI/UX: 0
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Comment (by 1st):
Replying to [comment:4 timgraham]:
> If it's widely used, then we should consider making it a public API and
documenting it. Perhaps you could give your rationale on the
DevelopersMailingList? If the function is meant as a general
"serialization" utility as you categorized the ticket, `forms.models`
seems like it might not be the best place to expose such functionality.
Does the Python serializer in `core.serializers` not work for your use
case?
Django `serializer` work very slow compared to my own implementation of
serialization. I compared it with what I created manually and I can save
about 50% of time on make response with serialized queryset. It's why I
get serialized list of objects and convert them to list of values that I
need.
Now I use this way to get list of model fields:
{{{
def get_model_fields(obj):
return sorted(options.concrete_fields, options.virtual_fields,
options.many_to_many)
}}}
But it will be better to get list of ALL model fields as simple call
`model_to_dict(obj, include_hidden=True)`
--
Ticket URL: <https://code.djangoproject.com/ticket/25198#comment:5>
Django <https://code.djangoproject.com/>
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