On Wed, Jul 31, 2013 at 7:39 PM, Loic Bistuer <[email protected]> wrote: > In your example "print qs[0]" evaluates a *clone* of "qs", not "qs" itself. > > Therefore "qs[0]; qs[-1]; qs[0]" triggers 3 queries, just like "qs[0]; qs[0]; > qs[0]" would. >
Fine, be pedantic: qs = ... print len(qs) print qs[0] print qs[0] This is one query. qs = ... print len(qs) print qs[0] print qs[-1] print qs[0] How many queries for this? -- You received this message because you are subscribed to the Google Groups "Django developers" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To post to this group, send email to [email protected]. Visit this group at http://groups.google.com/group/django-developers. For more options, visit https://groups.google.com/groups/opt_out.
