Hi Fons

I am detecting beeps on CW that happen about 1/second with a pulse length
of 18ms. At a decimated sampling rate of 10240 this equates to 189 samples.

I found that after the smoothing filter (orange line) I could calculate the
orange beep length and divide by 2 to get close to blue beep length.

The blue line as you guessed is after a filter and abs.

Al

On Mon, 1 Apr 2024, 22:21 Fons Adriaensen, <f...@linuxaudio.org> wrote:

> On Mon, Apr 01, 2024 at 01:50:32PM +1300, Al Grant wrote:
>
> > I have a block of code in my wildlife tracker that detects high/low beeps
> > in a frequency.
>
> It's not clear what the signal (blue trace in your png) actually
> represents and what exactly you are trying to do.
>
> - Detect any signal that exceeds the noise level by some margin ?
>
>   In that case S/N ratio makes sense.
>
> - Detect a signal at a particular frequency ?
>
>   In that case S/N isn't relevant, S/No (signal to noise density
>   ratio) is the relevant metric.
>
> So until you provide a bit more detail, just a few comments.
>
> I assume the signal (blue trace) is the absolute value or
> square of something - it must be nonnegative for what you
> do to make sense.
>
> >  samples = signal.convolve(samples, [1]*189, 'same')/189
>
> So you are convolving with a rectangular pulse in the time domain,
> which becomes a sinc in the frequency domain. This is not a very
> good choice. If you are convolving anyway (there may be simpler
> solutions), better use a shape that transforms to a good lowpass
> filter. This would be a truncated or windowed sinc in the time
> domain.
>
> > 189 is the number of expected samples
>
> What do you mean by 'expected' ? Why 189 ?
>
> > 1. Beep length calculations are off because of the extended
> > length of "high samples"
>
> Look at the points in your plot where the orange line intersects
> the blue pulse. This happens at half the peak value of the orange
> trace. A threshold at that level will give you a good estimate of
> the pulse lenght.
>
> > 2. SNR calculations are considerably higher (and I am not sure
> > which SNR is "correct")
>
> Which may be because S/N isn't the relevant parameter (see above).
> You need to provide more details about what comes before (how
> you get the blue signal).
>
> Ciao,
>
> --
> FA
>
>
>
>

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