Hi Jeff,
Thanks again for your recent response to my posted questions, but it was
not explicit enough to help me extract the values I wanted from the pmt
list and dictionary.
Based on the following pmt definitions for a list and dictionary. How do I
extract the 1st element in the list and the value of the key 'spam'?
P_list = pmt.to_pmt([1, 2, 3.45, 'eggs'])
P_dict = pmt.to_pmt({'spam': 20, 'eggs': 40})
Thanks!
George
On Fri, Jul 29, 2022 at 2:58 PM Jeff Long <willco...@gmail.com> wrote:
> k = pmt.intern('spam')
> nil = pmt.get_PMT_NIL()
> v = pmt.dict_ref(d, k, nil)
>
> The last argument to dict_ref is what gets returned if the key is not
> found.
>
> On Fri, Jul 29, 2022 at 11:13 AM George Edwards <gedwards....@gmail.com>
> wrote:
>
>> Hello GNURadio Community,
>>
>> I am creating a Python OOT block to send/receive pmt list and pmt
>> dictionary messages. In both cases, I am having problems extracting the
>> elements in the message. Let's assume (some trivial values):
>> P_list = pmt.to_pmt([1, 2, 3.45, 'eggs'])
>> P_dict = pmt.to_pmt({'spam': 20, 'eggs': 40})
>>
>> How do I extract individual elements from P_list and P_dict? Nothing I
>> tried worked.
>>
>> I appreciate any help.
>>
>> Regards,
>> George
>>
>
