Hi Marcus, Thanks for offering to assist me.
The OOT signal processing blocks I have designed so far worked with streaming data. For this project, I wish to pass the data in as vectors (which is new to me). I am writing this OOT block to accept a vector of 100 floating point elements on each iteration. I wrote the QA Test so I can use the Debugger to parse the C++ code and get an understanding of how vector elements are passed into a block. For the QA Test, I restricted the vector size to 4 floating pointing elements (something I can observe easily for debugging purposes) and I set the I/0 signatures accordingly: sizeof(float)*4. Inside the QA file I set the input to data = (1.0, 2.0, 3.0, 4.0). My initial assumption was that I am passing in a vector of length 4 floating point elements. The test failed and gave an error message of data mismatched because the signature input was 16 (4*4 bytes/float) and the QA input was 4 (meaning it saw data in stream format one float at a time and not as one big vector with 4 elements). Then, I tried rewriting: data = numpy.array([[1.0, 2.0, 3.0, 4.0], [5.0, 6.0, 7.0, 8.0]]) Thinking, I am forcing things to look like vectors of size 4 elements, WRONG AGAIN! So I am seeking help on how to feed in vectors from a QA file into a block that needs its data in vector form. Thank you! Regards, George On Thu, Apr 21, 2022 at 3:57 AM Marcus Müller <mmuel...@gnuradio.org> wrote: > You'll have to tell us what you do with that `data` and what the > io_signature of your > block is. > > On 20.04.22 17:22, George Edwards wrote: > > Hello GNURadio Community, > > > > In an OOT QA testing of a signal processing block designed to accept an > input vector of 4 > > elements, I am having problems passing the QA input as a vector. It sees > the input as a > > stream. I tried passing the data in two ways, but each failed. Here are > the two ways I > > have formated the QA data which I would like to be seen as a vector of 4 > elements: > > > > data = (1.0, 2.0, 3.0, 4.0) and > > data = numpy.array([[1.0, 2.0, 3.0, 4.0], [5.0, 6.0, 7.0, 8.0]]) > > > > I would appreciate any suggestion. > > > > Thank you! > > George > >
