Hi Md. Atiqur, On Fri, 2020-02-14 at 20:43 +0100, Md. Atiqur Rahman wrote: > For a QPSK modulation technique, I choose to set constellation point 1 to -1, > hence 1.4142 would be amplitude
Ah, you're confusing the magnitude of the complex number with the amplitude of the I and Q component. So, yes, the magnitude of (1 + 1j), (1 - 1j), (-1 + 1j) and (-1 -1j) are 1.41, but the real and imaginary parts are still +-1. > but in the timing diagram, it looks less than that. So, that's correct :) > Another point is, as my sampling rate is 2Mhz, and samples per symbol are 32, > hence 62.5K is the symbol rate, what will be my baseband signal frequency? 0 Hz. That's what "baseband" means. Best regards, Marcus PS: As someone occasionallly advising students, I'd recommend you clean up your flow graph; there's blocks in there you've commented out that you can never use (WX can't coexist with QT GUI). Also, try to make it as linear as possible, so to make it really easy to follow the "sample flow" optically. This is the Nr. 1 debugging hint for GRC beginners, and it really helps a lot when talking about a flow graph. Also, by the way, you're using a legacy GNU Radio. We've released GR 3.8, and you're still on 3.7.; the new GNU Radio has fewer bugs, and vector export for GRC figures, which is important to anyone writing a thesis with GRC flow graph pictures ;)
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