The method I want to call is thread-safe, and the target block doesn't support the required message. Regardless, I only need it for quick prototyping so I don't care at this stage if this is clean or not. This is an experimental GRC flowgraph for me. How do you pass a reference to the target block, or to the top block, from GRC GUI, to my custom block?
On Thu, Mar 22, 2018 at 5:32 PM Johannes Demel <de...@ant.uni-bremen.de> wrote: > Hi Gilad, > > it is possible to pass references to other blocks to your custom block. > But you should avoid this implementation. First off, another block is > scheduled in another thread. This might cause runtime issues. > > If you need status information from another block, add a message port > that outputs this information. Make it useful to everyone and upstream > your additional functionality. > > If you want to update the internal status of another block. Definitely > use message ports to set internal variables. > > Cheers > Johannes > > On 22.03.2018 14:34, Gilad Beeri (ApolloShield) wrote: > > I have a block I implemented, and I use it inside a GRC flowgraph with > > many in-tree blocks. > > I want to reference one of those blocks from my own block (call one of > > its methods). > > > > Is it possible in GRC without manual modification of the generated > > Python file? > > > > > > _______________________________________________ > > Discuss-gnuradio mailing list > > Discuss-gnuradio@gnu.org > > https://lists.gnu.org/mailman/listinfo/discuss-gnuradio > > > > _______________________________________________ > Discuss-gnuradio mailing list > Discuss-gnuradio@gnu.org > https://lists.gnu.org/mailman/listinfo/discuss-gnuradio >
_______________________________________________ Discuss-gnuradio mailing list Discuss-gnuradio@gnu.org https://lists.gnu.org/mailman/listinfo/discuss-gnuradio
