On 08/12/2015 05:39 PM, West, Nathan wrote:
On Wed, Aug 12, 2015 at 12:31 PM, West, Nathan <n...@ostatemail.okstate.edu <mailto:n...@ostatemail.okstate.edu>> wrote:On Wed, Aug 12, 2015 at 10:51 AM, Gerome Jan L <geromejanlla...@gmail.com <mailto:geromejanlla...@gmail.com>> wrote: There is an internal scaling effect of |fftlen| (the length of your FFT) in the FFT block. How do I unscale or remove the scaling factor in the python generated by thr GRC? I tried the one suggested in the faq, |... forward FFT --> multiply_const_cc(fftlen*[1.0/fftlen,]) --> reverse FFT ... | |but it doesn't seem to work. I know I am missing something. How do I insert this into this line of code in my python? 1. self.fft_vxx_0 = fft.fft_vcc(1024, True, (window.rectangular(1024)), True, 1) | |or here? 2. self.blocks_complex_to_mag_squared_0 = blocks.complex_to_mag_squared(1024) | |Thank you in advance. | | | |Attached is my flow graph. | Best, *Gerome Jan M. Llames * "Design is not just what it looks like and feels like. Design is how it works." - Steve Jobs What do you expect the constant to be? fftlen*[1.0/fftlen,] = [1], unless I'm having a really slow day. It's been pointed out to me that I am having a slow day. Taking a step back... when you say "it doesn't seem to work", what exactly does that mean? What do you observer that is different from what you expect? _______________________________________________ Discuss-gnuradio mailing list Discuss-gnuradio@gnu.org https://lists.gnu.org/mailman/listinfo/discuss-gnuradio
Try multiply_const_cc( 1.0/fftlen, vlen=fftlen ) - Jeff _______________________________________________ Discuss-gnuradio mailing list Discuss-gnuradio@gnu.org https://lists.gnu.org/mailman/listinfo/discuss-gnuradio
