Hi Rich, > What happens when you assign input to output in a general_work call, > out[ii]=in[ii], but don't call produce? Then you're breaking a contract! GNU Radio has to rely on you only writing samples you admit that you produce -- otherwise, the write pointer can't advance, and the next general_work will be offered the same buffer space again. > My minds eye sees the out variable as a secondary local buffer for > general_work. There is no local buffer! You directly work on the pseudocircular buffers; everything else would introduce unnecessary copy overhead.
Best regards, Marcus On 06/24/2015 09:23 PM, Richard Bell wrote: > What happens when you assign input to output in a general_work call, > out[ii]=in[ii], but don't call produce? Is the stuff you dumped into > 'out' lost when general_work returns WORK_CALLED_PRODUCE? > > My minds eye sees the out variable as a secondary local buffer for > general_work. You dump stuff in there while general_work has scope, > and transfer the contents of this buffer to the gnuradio block buffer > when you call produce. Am I understanding this correctly? > > v/r, > Rich > > > _______________________________________________ > Discuss-gnuradio mailing list > Discuss-gnuradio@gnu.org > https://lists.gnu.org/mailman/listinfo/discuss-gnuradio
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