I can't use sleep() here; because there're other threads as well in the program which need to be executed as well. Sleep() stop the execution of program; which is not a solution. Thanks.
On Thu, Nov 13, 2014 at 5:53 PM, Syed Aqeel Raza <s.aqeelr...@gmail.com> wrote: > Thanks Sylvain for your reply; but if I introduced sleep(14) then during > that time it won't perform the tasks in tb1 as well. > > On Thu, Nov 13, 2014 at 3:28 PM, Syed Aqeel Raza <s.aqeelr...@gmail.com> > wrote: > >> Hi All, >> >> I am looking for a solution that start() the flow graph for a definite >> period of time (in seconds) and after that it stop() it automatically. For >> example >> >> # let suppose initial value of time is 14 seconds; it means that the >> flowgraph defined in tb1 should need to executed during that time; and when >> the time reaches zero it must be stop. >> >> while 1: >> if (time!=0): >> tb1.run() >> time = int(time) - int(1) >> elif (time==0): >> tb1.stop() >> >> >> I tried this; but once the flow graph started; then it never comes to the >> elif condition. How can I stop() the flowgraph in this condition. Waiting >> for reply. >> >> Regards, >> >> >> >> > >
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