The question is ill-formed, the concept of a 'sampling rate' does not
really apply here.
However, to an item rate, you can do the math yourself:
Assume N is the FFT length, and CP the length of cyclic prefix in
samples. r is the incoming sampling rate.
First, data goes through the HPD, which takes out the CP. The outgoing
rate of that block is thus
r2 = (N+CP)/N * r
Actually, it's output is already OFDM symbols ("FFT-ready"). So, the
output item rate is
r3 = r2/N
Then, the packet header is removed. This further reduces the rate, but
let's ignore that. It's also dependent on the packet length.
Since the FFT doesn't change the rate, what you want is most likely r3.
M
On 10/06/2014 10:36 AM, xianda wrote:
> Hi all:
> Thanks in advance.
> Example:gnuradio/gr-digital/examples/ofdm/rx_ofdm.grc.
> If I set the sample rate of usrp equal to 1Msps,then what is
> the sample rate of the output of the FFT block?Thank you very much.
> Best regards,
> xd
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