On Wed, Aug 04, 2010 at 05:08:44PM +0800, intermilan wrote: > > hi all: > I recently run the test_usrp_standard_tx/rx.cc to do some test.and > after I run the test_usrp_standard_tx.cc, I got the follow information: > which: 0 > interp: 64 > rf_freq: 2.5e+09 > amp: 30000.000000 > nsamples: 3.2e+07 > Subdevice name is Flex 2400 Tx > Subdevice freq range: (2.3e+09, 2.7e+09) > mux: 0x000098 > baseband rate: 2e+06 > target_freq: 2500000000.000000 > ok: true > r.baseband_freq: 2504000000.000000 > r.dxc_freq: -4000000.000000 > r.residual_freq: 0.000000 > r.inverted: 0 > xfered 3.2e+07 bytes in 4 seconds. 8.002e+06 bytes/sec. cpu time = 0 > > as you can see, I want to set the frequency at 2.5G(RFX2400) ,but there > is a parameter called r.basebande=2.504G.I know it is the return valus of the > tune().but I want to know what is the function of this parameter and how did > 2.504G come out. can anyone help me to figure it out? > Besides,why the frequenct of the DUC is set at -4M? how did it come out?
It moves the DC offset 4MHz away from the center of your desired spectrum. r.baseband_freq + r.dxc_freq = target_freq. Eric _______________________________________________ Discuss-gnuradio mailing list Discuss-gnuradio@gnu.org http://lists.gnu.org/mailman/listinfo/discuss-gnuradio
