On 05/07/2010 06:44 PM, William Pretty Security Inc wrote:
Ok. I've almost got my scanner working, but I have a problem.
What does the "offset" parameter do in the signal source ??
The equation for the output of the signal source is something like this:
output[n] = amplitude*waveform[n] + offset
Look at the output of the waveform with the scope sink, it will be
clear. I think the ramp does not go below zero with an offset of zero.
Does it produce the equivalent of a DC off set?
For example if I want a ramp that goes from 0 to 2 volts, do I need an
offset of 1 (volt) ??
Probably an amplitude of 1 and an offset of 1, check the scope sink.
There is no voltage equivalent here. I call them units.
-Josh
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