On Sun, Apr 11, 2010 at 10:12 AM, Sebastiaan Heunis <sheu...@gmail.com> wrote: > Hi everyone. > > I was wondering if someone could please answer the following question? > > If I have two signals entering a receiver, both with a power of 0 dBm, > what would be the total input power seen by the receiver? Is it 3 dBm > or 6 dBm?
Bringing it back to power instead of ratios helps clear this up. Both transmitters are emitting 1mW, for a total input power of 2mW. Calculating dBm on that yields: 10*log10(2mW/1mW) = 3dBm Hope this helps! > Thanks. > > Sebastiaan Brian _______________________________________________ Discuss-gnuradio mailing list Discuss-gnuradio@gnu.org http://lists.gnu.org/mailman/listinfo/discuss-gnuradio
