So that is the reason for use .run() the gui will display if you py file is modified by a grc file, but if use the .start() function, no gui display even in same program?
if it is ture,how can I add some logic after the program started? I mean if I use start() function ,the code after start() could be executed (use run function these code could not be executed),but the GUI silde or ratiobottom item which add to file by GRC previously could not be displayed? Is there anyway to have both GUI item and some logic after program could be available in same time? 2009/9/5 Josh Blum <j...@joshknows.com> > run() is a blocking call. > start() is a non-blocking call. > > Also, I believe run() will exit when a block returns -1 in its work method. > FYI > > -Josh > > nansai hu wrote: > >> When run a python script file, as we know main function will be run >> first. >> We send the class to a object "tb",for instance. Then we have two ways to >> let the program run. >> One is call tb.run() function,and other is call tb.start() function.Could >> somebody told me the difference bewteen these? >> >> In my coding experience, use .run() the gui will display if you py file is >> modified by a grc file, but if use the .start() function, no gui display >> even in same program. >> >> >> >> ------------------------------------------------------------------------ >> >> _______________________________________________ >> Discuss-gnuradio mailing list >> Discuss-gnuradio@gnu.org >> http://lists.gnu.org/mailman/listinfo/discuss-gnuradio >> >
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