Hi, > On Fri, 3/20/09, kaleem ahmad <kaleem_...@yahoo.com> wrote: > > ADC sampling rate = 64MHz > it gives resulution time = 1/64MHz = 156 ns > if we choose N=512 for FFT then total observation time for > one scan(one > complete FFT) is = 156ns x 512 = 8 micro sec > if the maximum possible (expected) cycle time is 200ms > then: > it needs 200ms/8microsec = 2500 continues FFT scans to > cover the range of > frequencies that correspond to 200ms cycle time. > > Is above calculation correct? >
The above calculation is only true at FPGA level (ADC=64MHz). At PC side, max sampling is 8MHz (125nsec). So acquisition time for 512 FFT is 64 usec. If the frequency is constant, you can use DFT instead of FFT. Best Regards, Firas _______________________________________________ Discuss-gnuradio mailing list Discuss-gnuradio@gnu.org http://lists.gnu.org/mailman/listinfo/discuss-gnuradio
