On Jan 30, 2008 9:35 AM, TomasOMaille <[EMAIL PROTECTED]> wrote:
>
> Hello,
>
> I have been trying to understand the tx and rx data paths through the AD9862
> and the FPGA (standard configuration).
>
> RX side:
>
> - The two ADCs of the AD9862 push data onto two 12 bit buses
>
> - After the FPGA MUX the 16 bit I/Q signals pass into the assigned DDC
>
> - Are four extra bits assigned to the received I/Q when they arrive onto
> the FPGA?
Pretty much. In the DC offset removal process, they are assigned on
input. Here is where it happens:
http://gnuradio.org/trac/browser/gnuradio/trunk/usrp/fpga/sdr_lib/adc_interface.v#L34
You can see that the input of the rx_dcoffset module is assigned:
.adc_in({adc0[11],adc0,3'b0})
Which is a 1 bit sign extension, the 12 original bits, then 3 bits of 0's.
> TX side:
>
> - The 16 bit I/Q signals pass into the FPGA demux and arrive at the
> appropriate AD9862 chip
>
> - I/Q signals arrive interleaved on a 14 bit bus into the AD9862
>
> - Are the I/Q signals truncated by 2 bits before they are sent onto the 14
> bit bus?
Yes, as can be seen here:
http://gnuradio.org/trac/browser/gnuradio/trunk/usrp/fpga/toplevel/usrp_std/usrp_std.v#L179
Whatever 16-bits are coming from the tx_chain module is truncated by
2-bits and sent out the DACs.
Brian
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