I have attached the source file where the work method is contained. I cannot make any assumption on delta - it can be even or odd, the loss of precision because of the division by two is not going to be a problem though as there are many hundredths of samples per symbol (input sample rate to block is 256kbps). More, the consume on the signal works, infact on the next work invocation I get the signal samples the right way - the problem is on the clock cycle:
// From this point sync clk
//
d_sign_last = (clk[0] > 0 ? 1: -1);
for (i = 0; i < n_clk_in ; i++) {
sign_current = (clk[i] > 0 ? 1: -1);
if(sign_current != d_sign_last) {
// zc in clock
consume(1, i);
break;
}
d_sign_last = sign_current;
}
enter_locked();
return 0;
here I would expect to consume clock samples up to the first sample after
level transition; however if I graph clock on the next work
run, clock is NOT a the transition point.
If I change the code this way:
i=i-(delta/2);
d_sign_last = (clk[i] > 0 ? 1: -1);
...code as above follows...
so that search for clock transition is done not starting from sample #0,
but from a sample somehow near to where I actually am on signal so that
consume on channel 1 will be similar (in number of samples to consume) to
consume on channel 0, then I experience correct sample consuming and
clock/signal alignment on the next work cycle.
regards
Matteo iz2eeq
> On Wed, Jan 03, 2007 at 09:32:06AM +0100, Matteo Campanella wrote:
>> There is no forecast method implemented, and the main cycle is
>> structured
>> so that it is impossible to consume more than offered from scheduler
>> (see
>> http://lists.gnu.org/archive/html/discuss-gnuradio/2006-12/msg00253.html
>> for code posting).
>
> The code's a little hard to follow in the archive. However, this
> piece of code looks potentially suspicious. Is delta always even, or
> always odd? Are you sure that this is correct?
>
> consume(0, i-(delta/2));
>
> Eric
>
>
gr_rds_biphase_decoder.cc
Description: Binary data
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