Are you sure you get enough input items for the general_work? try to
print ninput_items and see what the result is. It might be that you
get always less than the 7 items you need to initialize the algorithm.
Thomas
On 10/10/06, Dawei Shen <[EMAIL PROTECTED]> wrote:
Hello Everyone
I have got a problem which arised from my project. Here is what I want to
do: I am trying to implement a Viterbi algorithm. Suppose "in" is the input
stream, I want to use in[0], in[1]....in[6], seven elements to initialize
the Viterbi algorithm. Then from in[7], I start to use Viterbi algorithm to
do tracking. Now the problem comes, in the "general_work()" function, I did
something like this:
int general_work(arg1, arg2, arg3, arg4) {
for (int i = 0; i < 7; i++) {
use in[i] to intialize the Viterbi algorithm;
}
for (int i = 8; i < ninput_terms; i++) {
use each in[i] to do Viterbi algorithm tracking;
out[n] = something
}
}
However, the results told me this is a wrong way. Because the initialization
part (the for i=0, i<7, i++ part) would be executed for many many times. It
appeared to me that the scheduler would try to call the general_work
function for many times and each time it calls it, everything in the
function would be executed from the beginning to the end. For example, if I
write a line
printf("can you see me?\n");
and put it in front of the first 'for' iteration, I can see the printed
output many times. This thing totally disturbed what I wish to do. Am I
understood?
Could anyone provide any help or insights? Thanks in advance.
Best Regards
Dawei
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