Le 07/04/2019 à 19:16, Seb via Digitalmars-d-learn a écrit :
Then you can do:

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["a": 1].byPair.array.sort!((a, b) => a.value < a.value).release.each!writeln;
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You'll have a sorted array with key and value props.

That's what I would do: just operating on an array of {k,v} pairs.

--
diniz {la vita e estranj}

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