Re: typeof function literals which define the types of its parameters but do not give their parameters names

[Adam D. Ruppe via Digitalmars-d-learn]

On Thursday, 27 December 2018 at 15:39:23 UTC, Steven 
Schveighoffer wrote:
A template evaluating to a type void is how 
is(typeof(someTemplateDefinition)) works.

Yeah, I know of that, but with __traits(isTemplate) now, I don't 
think there's any good reason to use the old hack detection 
anymore anyway.