On Sunday, 25 February 2018 at 16:22:19 UTC, ARaspiK wrote:
Instead of passing std.range.zip a set of ranges as different arguments, is it possible to hand the m a range of ranges, and get them to zip together each element of every subrange?
`std.range.transposed` does this, but it requires that the range of ranges has assignable elements, so it may not work in all cases. For example:
import std.range; import std.algorithm.iteration; import std.stdio; auto rr1 = [[1, 2, 3], [4, 5, 6]]; rr1.transposed.each!writeln; // Works auto rr2 = only(only(1, 2, 3), only(4, 5, 6)); rr2.transposed.each!writeln; // Doesn't work
