Re: problem with std.variant rounding

[via Digitalmars-d-learn]

On Friday, 28 April 2017 at 16:24:55 UTC, Suliman wrote:
On Friday, 28 April 2017 at 15:45:25 UTC, Suliman wrote:
I am using https://github.com/mysql-d/mysql-native
It's return from DB variant data-type.
My DB include value: 56.051151 (double type in DB)

I need to extract it. I tried several variants:

writeln(point[3].coerce!float);
writeln(point[3].coerce!string);
writeln(point[3].coerce!double);

but all of them return me it as: 56.0512

How to return exactly 56.051151 ?

import std.stdio;
import std.variant;

void main()
{
        Variant b = 56.051151;
        float x = b.coerce!float;
        writeln(x);
}

56.0512

The precision is still there, you're just not requesting it:

import std.conv : text;
import std.stdio;
import std.variant;

void main()
{
    Variant b = 56.051151;
    float x = b.coerce!float;

    foreach (i; 0 .. 10)
        writefln(text("%.", i, "f"), x);
}

56
56.1
56.05
56.051
56.0512
56.05115
56.051151
56.0511513
56.05115128
56.051151276

How to return exactly 56.051151 ?

Specify the number of digits after the decimal point manually, 
e.g. writefln("%.6f", x) will print 56.051151.