On Sunday, 31 January 2016 at 17:55:53 UTC, Matt Elkins wrote:
Errr, ignore the makeFoo() line. Left that in by accident, has no bearing on the issue.
Ok, I think I understand why this doesn't work, at least. The Foo passed into bar() is, of course, an lvalue itself.
So I can achieve this with a new bar(), like so:
[code]
void bar(Foo foo)
{
import std.algorithm.mutation;
Foo foo1 = move(foo);
}
[/code]
