On 11/21/15 10:19 PM, Jon D wrote:
On Sunday, 22 November 2015 at 00:31:53 UTC, Jonathan M Davis wrote:

Honestly, arrays suck as output ranges. They don't get appended to;
they get filled, and for better or worse, the documentation for copy
is probably assuming that you know that. If you want your array to be
appended to when using it as an output range, then you need to use
std.array.Appender.

Hi Jonathan, thanks for the reply and the info about std.array.Appender.
I was actually using copy to fill an array, not append. However, I also
wanted to preallocate the space. And, since I'm mainly trying to
understand the language, I was also trying to figure out the difference
between these two forms of creating a dynamic array with an initial size:

    auto x = new int[](n);
    int[] y;  y.reserve(n);

If you want to change the size of the array, use length:

y.length = n;

This will extend y to the correct length, automatically reserving a block of data that can hold it, and allow you to write to the array.

All reserve does is to make sure there is enough space so you can append that much data to it. It is not relevant to your use case.

The obvious difference is that first initializes n values, the second
form does not. I'm still unclear if there are other material
differences, or when one might be preferred over the other :) It's was
in this context the behavior of copy surprised me, that it wouldn't
operate on the second form without first filling in the elements. If
this seems unclear, I can provide a slightly longer sample showing what
I was doing.

extending length affects the given array, extending if necessary. reserve is ONLY relevant if you are using appending (arr ~= x). It doesn't actually affect the "slice" or the variable you are using, at all (except to possibly point it at newly allocated space).

copy uses an "output range" as it's destination. The output range supports taking elements and putting them somewhere. In the case of a simple array, putting them somewhere means assigning to the first element, and then moving to the next one.

-Steve

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