Re: How can I convert the following C to D.

[anonymous via Digitalmars-d-learn]

On Wednesday, 21 January 2015 at 23:44:52 UTC, anon wrote:
I have the following C code, how can I do the same in D.
Info **info;
info = new Info*[hl + 2];

int r;
for(r = 0; r < hl; r++)
{
        info[r] = new Info[vl + 2];
}
info[r] = NULL;

anon

The super-literal translation:
    Info** info;
    info = new Info*[hl + 2].ptr;
    int r;
    for(r = 0; r < hl; r++)
    {
        info[r] = new Info[vl + 2].ptr;
    }
    info[r] = null;

A little more D-ish:
    Info[][] info = new Info[][hl + 2];
    foreach(r; 0 .. hl)
    {
        info[r] = new Info[vl + 2];
    }
    assert(info[hl].length == 0); /* Relying on default 
initialization. */

D to the ultimate max:
    import std.algorithm;
    import std.range;
    auto info = iota(hl)
        .map!(i => new Info[vl + 2])
        .chain(only(Info[].init, Info[].init))
        .array;
    static assert(is(typeof(info) == Info[][]));
    assert(info.length == hl + 2);
    assert(info[hl].empty);

And if those +2 are for sentinel values, D doesn't need them 
because D arrays know their length. And it all comes down to:
    auto info = new Info[][](hl, vl);