On Saturday, 20 July 2013 at 20:36:29 UTC, Ali Çehreli wrote:
On 07/20/2013 12:34 PM, Alex Horvat wrote:
> If I use core.thread.Thread to create a new thread associated
to a
> function like this:
>
> Thread testThread = new Thread(&DoSomething);
>
> Will the testThread dispose of itself after DoSomething()
completes, or
> do I need to join/destroy/somethingelse testThread?
When the execution of the thread finishes, you will end up with
a completed thread:
import std.stdio;
import core.thread;
void DoSomething()
{
writeln("Doing something...");
}
void main()
{
auto thread = new Thread(&DoSomething);
thread.start();
thread_joinAll();
assert(!thread.isRunning); // <-- Not running
}
You do not need to do anything with the object. In fact, the
documentation says that you shouldn't delete it: "instances of
this class should never be explicitly deleted". ('delete' is
gone, so it should mean that you shouldn't destroy() it.)
Ali
Thanks.
What happens if I don't call thread join? (My thread is just a
timer to hide a bit of text, so I just create it, forget about it
and continue with the main thread)
Will the thread still dispose of itself in this situation?
