Hi.I want to extend math library functions to work with my own type. However, the definition for my own type seems to prevent automated access to the original function. How can I fix this unexpected behavior?
Simplified example:
--------------------
import std.math;
int exp2(int x) {
return 1 >> x;
}
void main() {
assert(exp2(0.0) == 1.0); // <= why does not
this work anymore?
//assert(std.math.exp2(0.0) == 1.0); // <= this works
}
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