On Monday, 2 October 2023 at 21:37:56 UTC, bachmeier wrote:
On Monday, 2 October 2023 at 19:28:32 UTC, BoQsc wrote:I'm unable to see how the operator overloading would allow to define a new custom operator.And I don't expect that to change. This has come up many times.
With a parameter that has a symbol-like name you can use it like `x.mod(y)`, which looks alright too.
