On 12/12/22 12:23 PM, lili wrote:
``` int[string] aa = ["ok":1, "aaa":2, "ccc":3, "ddd":4]; foreach (k ; aa.byKey) { if (k == "aaa") { aa.remove(k); aa["ww"] = 33; }if (k == "ww") { aa.remove(k); aa["vv"] = 33; } } writeln(aa); // output ["ok":1, "ddd":4, "vv":33, "ccc":3] is ok ```
Removing keys while iterating is not supported. It will break, in confusing ways, and possibly include a null pointer dereference.
Instead, either iterate over `aa.keys`, which makes a copy of the keys into an array, store the keys to remove for later processing, or construct a new AA with the indicated keys removed.
-Steve
