Re: How ptr arithmitic works??? It doesn't make any sense....

[rempas via Digitalmars-d-learn]

On Monday, 5 December 2022 at 18:01:47 UTC, ag0aep6g wrote:

You can use bracket notation with pointers. You just need to move your closing parenthesis a bit.

Assuming that `ptr` is a `void*`, these are all equivalent:

```d
(cast(int*) ptr)[i] = whatever;
*((cast(int*) ptr) + i) = whatever;
*(cast(int*) (ptr + i * int.sizeof)) = whatever;
```

Oh, wow! That's sure interesting! Thanks a lot!