On Wednesday, 3 August 2022 at 19:11:51 UTC, pascal111 wrote:
On Wednesday, 3 August 2022 at 18:53:35 UTC, jfondren wrote:
On Wednesday, 3 August 2022 at 18:33:37 UTC, pascal111 wrote:
I changed it to "x=notfunny(x);" and has the same result.
Now you are changing the value of the temporary loop variable
that is still immediately discarded afterwards.
You should return a new range that has the values you want,
not try to mutate the range you're given.
You should provide a code instead of describing my mistakes!!
No need for a code. See, there is a keyword called `ref`, that
can be used both in function parameters and in foreach loops, and
it is the equivalent of a pointer to the type specified, but it
is automatically dereferenced. As arrays are themselves reference
types, you don't need to change the parameter from `Range range`
to `ref Range range`.
On the other hand, `int` in it of itself isn't a reference type,
meaning that to modify the actual value, you need to change the
foreach loop to be:
```d
foreach(ref x; range)
x = notfunny(x);
```
Proof: I tested it, and it works.
